Contract: 4![]() Lead: ? |
NORTH (dummy)![]() ![]() ![]() ![]() |
NorthSouth have 9 easy tricks in hearts.
It is clear that if West starts with a diamond, then
NorthSouth will score 3 diamond tricks, 3 hearts
and 4 spades.
Without a diamond lead, a tenth trick seems
impossible with the
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WEST![]() ![]() ![]() ![]() |
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EAST![]() ![]() ![]() ![]() | |
SOUTH![]() ![]() ![]() ![]() |
A spade lead gives nothing away immediately, leaving
declarer with the 9 easy tricks he started with. Declarer
wins the spade, and knocks out the
![]() ![]() ![]() Declarer now pulls trumps and runs spades leaving the illustrated position with EastWest still having to make two discards.
West is in a bind. Two pitches in the same minor will surrender
an extra trick in that suit so suppose West
pitches one of each minor. South
will cash the The analysis is identical on an opening heart lead. |
NORTH (dummy)![]() ![]() ![]() ![]() |
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WEST![]() ![]() ![]() ![]() |
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EAST![]() ![]() ![]() ![]() | ||
SOUTH![]() ![]() ![]() ![]() |
Trumps must be drawn before the spades are cashed, and it seems like East will gain control of the hand by forcing South. However, South (if careful) can still make the hand on a dummy reversal.
NORTH (dummy)![]() ![]() ![]() ![]() |
Suppose East wins the first heart lead and taps declarer with
a high club. Declarer now crosses to dummy's
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If East ducks two hearts (see figure) then South cannot play a
third trump because East will tap out declarer to
establish the fourth defensive trick.
Again, declarer can engineer two club ruffs in hand by
crossing to the |
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WEST![]() ![]() ![]() ![]() |
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EAST![]() ![]() ![]() ![]() | ||
SOUTH![]() ![]() ![]() ![]() |
All of the submissions were excellent! I look forward to seeing more solutions in the coming months!
Honourable Mention